How to create a large size struct array?
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I know I can create a struct array use struct function:
a = struct('data',{1,2,3});
But what if I want to create a 30d (or larger) struct array? Like:
a = a = struct('data',{1,2,3, ..., 30});
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Santa Raghavan
2017-7-26
编辑：Santa Raghavan
2017-7-26
s = struct | struct(field,value) | struct(field1,value1,...,fieldN,valueN) | struct([]) | struct(obj)
My understanding is that you are trying to create a single field struct with large number of values inside it. Looking at the type of the "value" argument in the constructor, here is something that would work for your specific use case:
a = struct('data',num2cell(1:30))
If you intend to create a field and populate it with large number of values in a loop, the easiest way would be to create a cell array obj and then use this as the value argument to construct the struct.
C = {};
for i = 1:30
C{i} = i;
end
a = struct('data',C);
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