Inverse Z-Transform of z/(z-a) - Strange result

5 次查看（过去 30 天）
Gennaro Arguzzi
Gennaro Arguzzi 2017-7-26
评论： fadli yusuf 2020-12-23
Hello everyone, I tried to get the inverse Z-transform of z/(z-a) with the following lines:
close all
clear all
syms a n z
iz=iztrans(z/(z-a),z,n)
the result is:
piecewise([a == 0, kroneckerDelta(n, 0)], [a ~= 0, a*(a^n/a - kroneckerDelta(n, 0)/a) + kroneckerDelta(n, 0)])
but I expect a^n. How can I get a^n?
Thank you for your time.
  1 个评论
Karan Gill
Karan Gill 2017-7-26
To add to Star Strider's answer below, your result contains the piecewise function. See that doc page for more info.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Star Strider
Star Strider 2017-7-26
Specify ‘a>0’, and simplify:
syms a n z
assume(a > 0)
iz=iztrans(z/(z-a),z,n);
iz = simplify(iz);
iz =
a^n

更多回答（1 个）

Arthur Ngnepiepaye
Arthur Ngnepiepaye 2020-11-6
Can someone help me out plotting this zero input response? It's confusing

类别

在 Help Center 和 File Exchange 中查找有关 z-transforms 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by