Repeating elements in a matrix.

2 次查看（过去 30 天）
Gratitude Kim
Gratitude Kim 2017-7-27
评论： Gratitude Kim 2017-7-27
A=zeros(3,4)
A =
0 0 0 0
0 0 0 0
0 0 0 0
>> [nRows,nCols] = size(A); A(1:(nRows+1):nRows*nCols) = 1
A =
1 0 0 0
0 1 0 0
0 0 1 0
Appreciate your kind assistance on how can I write so that my matrix becomes :
A=[1 1 0 0; 0 1 1 0; 0 0 1 1]
Thanks

请先登录，再回答此问题。

采纳的回答

Andrei Bobrov
Andrei Bobrov 2017-7-27
编辑：Andrei Bobrov 2017-7-27
A=zeros(3,4);
n = size(A,1);
A([1:n+1:end,n+1:n+1:end]) = 1
or
t = true(3,4);
out = tril(t,1) & triu(t);

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by