How can I vectorize the following code?
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main.m
I = imread('bear.png');
J = rgb2gray(imread('marked_bear.png'));
mask = I-J;
for r=1:size(I,1)
for c=1:size(I,2)
if(mask(r,c))
I = some_function(I, r, c);
end
end
end
imshow(I);
some_function.m
function I = some_function(I, r, c)
% some processing on image 'I'
I(r,c) = 255;
bear.png
marked_bear.png
采纳的回答
Image Analyst
2017-7-28
Like this:
I = imread('bear.png');
J = rgb2gray(imread('marked_bear.png'));
mask = I-J; % Weird, but okay...whatever.
I(mask~=0)=255;
4 个评论
Ba Ba Black Sheep!
2017-7-28
编辑：Ba Ba Black Sheep!
2017-7-28
Image Analyst
2017-7-28
To make a funciton
function I = MaskI(I, J)
mask = I - J;
I(mask ~= 0) = 255;
Usually people use logical operations to create masks that are binary images, not arithmetic ones that produce integer images, that may depend on clipping, and then which still have to use logical operations anyway, such as mask ~=0. Most people, seeing what you intend, would have done:
mask = I ~= J;
and most people who write code for industry that needs to be maintained would use more descriptive variable names than I and J. I know Mathworks doesn't because they want their demo code to look as simple as possible, but I wouldn't let them write code like that in my company.
Ba Ba Black Sheep!
2017-7-29
Image Analyst
2017-7-29
OK, then...
function I = some_function(I, J)
mask = I - J;
I(mask ~= 0) = 255;
There. It's vectorized, still has a function, and that function is called "some_function" (instead of MaskI as I had called it), just like you asked for.
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