How to read string data from a csv file?
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Hello.. I have a csv data file with 6columns. First column is string type and others are numeric. I don't know why I cant read data with 'csvread'. I saved csv file as xls then used xlsread. It can read my data but it's not reading 1st column may be because its a string. 1st column is like yyyy-mm-ddThh:mm:ss Is there any way to read 1st column and then split it into two columns, one for date and other for time? how to read this data using csvread as I don want to convert it to xls. Thanks
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KSSV
2017-8-1
0 个投票
Use xlsread. Read about it.
3 个评论
Kavita Navria
2017-8-1
KSSV
2017-8-1
[num,txt,raw] = xlsread('myfile')
This read entire data.....
Kavita Navria
2017-8-1
更多回答（2 个）
Even simpler than xlsread is to use readtable which should be able to figure out the file format on its own.
data = readtable('yourfile.csv');
In particular, readtable should automatically detect that the first column is a datetime and decode it properly. If not it's trivial to convert it:
data(:, 1) = datetime(data(:, 1), 'InputFormat', 'yyyy-MM-ddTHH:mm:ss'); %or similar
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Guodong Cui
2018-8-17
readable is simple & useful! It works for me. Thank you!
Md Khaled Ben Islam
2018-4-15
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CHIA HUNG MOU
2023-12-31
编辑：CHIA HUNG MOU
2023-12-31
Yes. readtable is good. For your reference:
% data: https://chris.userweb.mwn.de/book/pizza_delivery.csv
fn = fullfile('pizza_delivery.csv');
data = readtable(fn);
% time
y = cell2mat(table2cell(data(:, 3)));
% interception
x1 = ones(1, size(y,1));
% binary variable (so called dummy variable)
x2 = zeros(1, size(y,1));
x2_ = (table2cell(data(:, 4)));
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