How do I draw zero level set of a function in matlab? (Based on my knowledge, it would be a sphere)

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I attached my script here.
clear
N=4; k=[0:N/2-1 0 -N/2+1:-1]; l=[0:N/2-1 0 -N/2+1:-1]; m=[0:N/2-1 0 -N/2+1:-1];
t=0; dt=.01; T=200; eps=.01; % epsilon in the equation; Meps=1/eps; Mv=100; Ma=100; r0=1;
phi0=zeros(N,N,N);
for i=1:N for j=1:N for n=1:N
fun1 = @(x,y,z) [cos(pi*(k(i)*x+l(j)*y+m(n)*z))-1i*sin(pi*(k(i)*x+l(j)*y+m(n)*z))].*tanh((r0-sqrt(x.^2 +y.^2 +z.^2 ))/eps);
phi0(i,j,n)=integral3(fun1,-1,1,-1,1,-1,1);
end
end
end

采纳的回答

Steven Lord
Steven Lord 2017-8-2
Use an isosurface as shown on this documentation page.

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