How to extract every elements with different dimension at multiple cells in efficient manner?

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balandong
balandong 2017-8-2
编辑： balandong 2017-8-3
Dear all,
Say I have three cells, where the element
dd = [49;50;51;52;53;54] [55;56;57] [85;86;87;88;89;90]
The objective is to extract all the element in each cell and make it into single row, such that
[40 50 51 52 53 54 55 56 57 85 86 87 88 89 90]
I used the following lines.
C =1
for i =1:size(dd,2)
Xcx = cell2mat (dd (1,i));
ee =[]
ee (1,1: length (Xcx)) =Xcx;
for k =1: length (ee )
new (C,1) = ee (k)
C =C+1
end
end
Even though the code do the trick, I am looking if there is more advance and compact ways of doing it?
Thanks in advance

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采纳的回答

balandong
balandong 2017-8-3
编辑：balandong 2017-8-3
Dear Akira, Thanks for your response, I give an idea of using the VERTCAT. Using VERTCAT instead of HORZCAT skip the need of CELLFUN and TRANSPOSE.
dd = {[49;50;51;52;53;54], [55;56;57], [85;86;87;88;89;90]};
output1 =vertcat (dd{:});
Thanks for your answer, however I had to accept this solution as a better and more compact ways.

更多回答（2 个）

Sanjay Nair
Sanjay Nair 2017-8-2
Hello,
If I'm understanding your problem correctly you have a cell array that can be defined in the following manner
dd = {[49;50;51;52;53;54], [55;56;57], [85;86;87;88;89;90]};
Since you have a cell array of column vectors with only three elements, perhaps the easiest way to extract them into a single row vector would be to transpose and concatenate the contents in a single command as follows:
row = [dd{1}', dd{2}', dd{3}'];
You can get more information about accessing data in cell-arrays in: https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-cell-array.html
  1 个评论
balandong
balandong 2017-8-3
HI Sanjay, Thanks for your response and idea. Your suggestion maybe effecient for few cell arrays. However, I want to generalize the code so that it can handle many cell array, say, > 20 cell arrays. I dont think it is a godd practice to do as following
row = [dd{1}', dd{2}', dd{3}', dd{4}', dd{5}', dd{6}', dd{7}', dd{8}', dd{9}', dd{10}', dd{11}', dd{12}', dd{13}', dd{14}', dd{15}', dd{16}', dd{17}', dd{18}', dd{19}', dd{20}'];

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Akira Agata
Akira Agata 2017-8-3
How about using cellfun and horzcat functions as follows. In this code, each element in cell array dd is transposed by cellfun. Next, horzcat concatenate each element horizontally.
dd = {[49;50;51;52;53;54], [55;56;57], [85;86;87;88;89;90]};
ddTrans = cellfun(@transpose,dd,'UniformOutput',false);
Output = horzcat(ddTrans{:});

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