what is mean by this
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ES
2017-8-3
S is an array of structures.
xd is one of the members of the structure (type unknown).
In the given line, member xd of the i'th structure is updated with a random number (generated using rand function) multiplied by xm.
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Star Strider
2017-8-3
It sets the ‘xd’ field of the i-th element of structure ‘S’ to rand times a variable called ‘xm’. The ‘(1,1)’ argument to rand is redundant, since a single call to rand returns a single random scalar value.
4 个评论
Star Strider
2017-8-3
Please see the documentation on structures that I linked to in my Answer.
It explains their use and addressing much better than I can.
Jan
2017-8-3
@Junaid Qadar: The forum is not the best location to clarify the basics of Matlab. Please read the documentation of the concerned command and the Getting Started chapters for this. See also https://matlabacademy.mathworks.com/ -> Onramp
ES
2017-8-4
编辑:ES
2017-8-4
There are a number of nodes in your problem - denoted by "NumberOfNodes".
xd, yd, E, R are properties of each of these nodes. The properties of the nodes are stored in a array of structures in this case. where S(1) denotes the properties of Node 1 and so on.
The piece of code you have put, sets the properties for all the nodes iteratively.
xd is set to random number * width;
yd is set to random number * depth;
E is set to E0
R is set to R0
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Abilasha
2023-7-25
kindly explain this code, its in leach protocol matlab code
figure(1);
for i=1:1:n
S(i).xd=rand(1,1)*xm;
S(i).yd=rand(1,1)*ym;
S(i).G=0;
S(i).type='N';
temp_rnd0=i;
1 个评论
Walter Roberson
2023-7-25
xd is set to a random number times xm. In other words the x coordinate is set to a random position in the range 0 to xm (maximum x). Likewise the y coordinate is set to a random location in the range 0 to ym.
(Note: the results can never be exactly 0 or exactly xm or ym because of the details of rand().)
You are generating a random position inside a rectangle.
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