0 个投票

h=0.1;
t1=0:h:2*pi;
alpha=0.3;
f=@(x) sin(x);
for i=2:length(t1)
t=t1(i);
k=1/gamma(1-alpha);
w=@(s) (t-s).^(-alpha).*cos(s);
p(i)=integral(w,0,t);
end

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TheStranger
TheStranger 2017-9-1
Hello Sameer. Sorry for the offtop, but have you tested, whether a vectorized version is faster than just looping? I tried "integral" function with "ArrayValued=1" and it turned out that it is 20% slower than just looping over the parameter, for example.

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 采纳的回答

Walter Roberson
Walter Roberson 2017-8-6

1 个投票

alpha=0.3;
syms s t
w = int((t-s).^(-alpha).*cos(s), s, 0, t);
h=0.1;
t1=0:h:2*pi;
p = double(subs(w, t, t1));

更多回答（1 个）

Andrei Bobrov
Andrei Bobrov 2017-8-6
编辑：Andrei Bobrov 2017-8-6

0 个投票

h=0.1;
t1=0:h:2*pi;
p = arrayfun(@(t)integral(@(s)(t-s).^-alpha.*cos(s),0,t),t1)

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