First input argument must be a function handle.

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Sergio Manzetti 2017-8-10

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https://ww2.mathworks.cn/matlabcentral/answers/352262-first-input-argument-must-be-a-function-handle

评论： Sergio Manzetti 2017-8-10

采纳的回答： KSSV

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Hi, I am trying to integrate using the following function:

if true
syms h g x pi
h = 2.0545
g = 5.3442
C = 1
y = C - (exp(-2.*g.*i.*x./h)).*(C - cos(x).*((h.^2)./2) + (g.*x)/2.*h.*i)
yx = integral(y,-pi,pi)
end

however, I get the error "First input argument must be a function handle. "

Can anyone suggest a solution?

Thanks!

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采纳的回答

KSSV 2017-8-10

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/352262-first-input-argument-must-be-a-function-handle#answer_277506

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h = 2.0545 ;
g = 5.3442 ;
C = 1 ;
y = @(x) C - (exp(-2.*g.*1i.*x./h)).*(C - cos(x).*((h.^2)./2) + (g.*x)/2.*h.*1i) ;
yx = integral(y,-pi,pi)

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José-Luis 2017-8-10

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y = @(x) ((C - (exp(-2.*g.*i.*x./h)).*C) * ((C - (exp(-2.*g.*-i.*x./h)).*C);

In your anonymous function the @(x) is not the symbolic variable x.

Sergio Manzetti 2017-8-10

Thanks. It must have function and not a result or call to another function in other words..?

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