Function [output]=F​unctionNam​e(input)

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Lisa Lee
Lisa Lee 2017-8-12
评论： Steven Lord 2020-9-21
I don't understand why sometimes a pair of brackets is used when a function is created. I have seen it in two cases:
1. the output is empty 2. the output is logical
Can someone please help me to clarify the scope of using a pair of brackets for the output when a function is created?

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采纳的回答

per isakson
per isakson 2017-8-12
编辑：per isakson 2017-8-14
Go to Create Functions in Files and look for Syntax for Function Definition. It says:
Output arguments (optional)
If your function returns one output, you can specify the output name after the function keyword. [...] If your function returns more than one output, enclose the output names in square brackets.
function [one,two,three] = myFunction(x)
The brackets are optional with zero and one output.
The Matlab template includes the brackets
function [ output_args ] = Untitled( input_args )
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
end
I guess, this template encourage the use of brackets with zero and one output.
  2 个评论
Jan
Jan 2017-8-12
Explicitly:
function [] = Untitled( input_args )
% is equivalent to:
function Untitled( input_args )
And
function [out] = Untitled( input_args )
% is equivalent to:
function out = Untitled( input_args )
Lisa Lee
Lisa Lee 2017-8-12
Thank you. This helps to clarify things for me.

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更多回答（1 个）

Jaya Agnihotri
Jaya Agnihotri 2020-9-21
function mfunc = minmod((ur-ul)/Delta_x,(ul-ul1)/Delta_x)
mfunc=0;
if sign(v)==sign(w)
mfunc=sign(v).*min(abs(v,w));
end
how to define this function in a right way?
  1 个评论
Steven Lord
Steven Lord 2020-9-21
In a function definition the input arguments must be variable names, not expressions.
% define
function mfunc = minmod(v, w)
% Do stuff to define mfunc here
end
In a function call you can pass expressions in and the results of those expressions are assigned to the variables listed in the definition.
% call
theOutput = minmod(1:10, sind(1:10))
% In this particular call, v will be 1:10 and w will be sind(1:10)

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