close all;clear all;clc;
f1=@(x) log(x+.01)+exp(x)-x*(log(x+.01)+exp(x))
x01=0;
options = optimoptions('fsolve','Display','iter');
options.MaxFunctionEvaluations = 1000
y1=fsolve(f1,x01,options)
f1 =
function_handle with value:
@(x)log(x+.01)+exp(x)-x*(log(x+.01)+exp(x))
options =
fsolve options:
Options used by current Algorithm ('trust-region-dogleg'):
(Other available algorithms: 'levenberg-marquardt', 'trust-region')
Set properties:
Display: 'iter'
MaxFunctionEvaluations: 1000
Default properties:
Algorithm: 'trust-region-dogleg'
CheckGradients: 0
FiniteDifferenceStepSize: 'sqrt(eps)'
FiniteDifferenceType: 'forward'
FunctionTolerance: 1.000000000000000e-06
MaxIterations: 400
OptimalityTolerance: 1.000000000000000e-06
OutputFcn: []
PlotFcn: []
SpecifyObjectiveGradient: 0
StepTolerance: 1.000000000000000e-06
TypicalX: 'ones(numberOfVariables,1)'
UseParallel: 0
Show options not used by current Algorithm ('trust-region-dogleg')
Norm of First-order Trust-region
Iteration Func-count f(x) step optimality radius
0 2 12.9973 377 1
1 4 4.02556 0.0344646 49.7 1
2 6 0.712178 0.0809282 7.6 1
3 8 0.050945 0.0937519 1.1 1
4 10 0.000680152 0.046356 0.0991 1
5 12 2.09695e-07 0.00686238 0.00168 1
6 14 2.17453e-14 0.000124849 5.41e-07 1
Equation solved.
fsolve completed because the vector of function values is near zero
as measured by the default value of the function tolerance, and
the problem appears regular as measured by the gradient.
<stopping criteria details>
y1 =
0.262487926852786
x02=100;
y2=fsolve(f1,x02,options)
Norm of First-order Trust-region
Iteration Func-count f(x) step optimality radius
0 2 7.08218e+90 7.15e+90 1
1 4 9.58373e+89 0.989999 9.68e+89 1
2 6 1.29689e+89 0.989899 1.31e+89 1
3 8 1.75496e+88 0.989797 1.77e+88
..
104 210 0.591762 0.36162 3.44 1.34
105 212 0.0156953 0.171887 0.383 1.34
106 214 4.06374e-05 0.0410109 0.0175 1.34
107 216 4.00574e-10 0.00232187 5.46e-05 1.34
108 218 4.0027e-20 7.33586e-06 5.46e-10 1.34
Equation solved.
fsolve completed because the vector of function values is near zero
as measured by the default value of the function tolerance, and
the problem appears regular as measured by the gradient.
<stopping criteria details>
y2 =
1.000000000073332
