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matrix dimension problem with integral

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Shan Chu
Shan Chu 2017-8-16
编辑： Torsten 2017-8-17
Dear all,
I have devloped this code and don't think there is any problem with is. However, Matlab returned an error on the matrix dimensions but I didn't use an array.
Could you please help? I also attached the file for the function expression.
Thanks
Ra_i=10.5e-3;
Ra_o=11.5e-3;
l1=1e-3;
mu=4*pi*1e-7;
n1=1;
A=@(x) integral(@(y) y.*besselj(1,x.*y),Ra_i,Ra_o);
fun_M=@(alp,gam) (gam.*(A(gam)).^2.*(sin(alp.*l1/2)).^2)./(alp.^2.*(alp.^2+gam.^2))
L=8*mu.*n1.*integral2(fun_M,0,Inf,0,Inf,'AbsTol', 1e-12,'RelTol',1e-12);

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Torsten
Torsten 2017-8-16
A=@(x) integral(@(y) y.*besselj(1,x.*y),Ra_i,Ra_o,'ArrayValued',true);
Best wishes
Torsten.
  2 个评论
Shan Chu
Shan Chu 2017-8-16
Thank you so much. it works Could you please explain why we need to assign this as an array?
Torsten
Torsten 2017-8-17
编辑：Torsten 2017-8-17
Take a look at the example "Vector-Valued Function" under
https://de.mathworks.com/help/matlab/ref/integral.html
Note that "gam" from integral2 will be a vector. So in order to calculate A(gam), you will have to activate the "ArrayValued=true" option.
Best wishes
Torsten.

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