How to split divide an array on specific sections?

Question

Jorge Rodriguez 2017-8-16

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评论： Jorge Rodriguez 2017-8-17

I have a double array of dimension (10000,5), the first column of the array is an ID going from 1-10. The other 4 columns are the related data. I'm trying to create individual arrays based on each ID value and the quantity of each ID can vary with respect to each other.

%For example:
%CA is the vector with the data =(ID,DATA1,DATA2,DATA3,DATA4)
%ID goes from 1-10
%The first array should be GC1=(1,DATA1,DATA2,DATA3,DATA4) with "x" number of rows
%I have tried to make this code work but I don't know what's wrong? I have a loop to create 11 array GC(id), although i now is not recommended.
k =size(ID,1); %size of vector, size of data base
    x=0;
    jl=1;
     CAA=zeros(k,1);
     CAA=CA(:,1); %extraction of the ID column from CA
for id=1:10
        for i=jl:k
           if CAA(i,1)==1
               x=x+1;         
           else
            GC(id)=zeros(x,5);
            GC(id)=CAA(jl:x,5);
           end
        end
end

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Answer 1

Sebastian Castro 2017-8-16

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https://ww2.mathworks.cn/matlabcentral/answers/353001-how-to-split-divide-an-array-on-specific-sections#answer_278204

编辑：Sebastian Castro 2017-8-16

在 MATLAB Online 中打开

You can do this with logical indexing. Say, for example, you want to grab the data whose ID corresponds to 5:

% Generate dummy data
% First column is a random number 1-10
data = [randi(10,100,1) rand(100,4)];
% Extract the data from those with ID #5
subset5 = data(data(:,1)==5,:);

- Sebastian

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Jorge Rodriguez 2017-8-16

Sebastian, do you know id there is a way to create the vector subset in a loop. In other words subset(i)? this is just in case the ID varies from more than 1 to 10? Thanks

Sebastian Castro 2017-8-16