Fill cell in second column based on first column cell array

6 次查看（过去 30 天）
Lauryn Burleigh
Lauryn Burleigh 2017-8-17
编辑： Stephen23 2017-8-17
I have a cell array of image names in the first column ('9_X_0_a.bmp', '9_X_0_b.bmp','19_X_0_a.bmp', '19_X_0_b.bmp', etc.). I would like to fill the second column with either '1' or '2' based on if the image names contain 'a' or 'b'.
I currently have the code set to run as an 'if' statement which works but only for one index. In other words, it will place the proper number in the second column for either 'a' or 'b' images, but not for both. Any advice?
for i = length(listOfFiles1);
indexa = find(contains(listOfFiles1, 'a'));
indexb = find(contains(listOfFiles1, 'b.bmp'));
if i == indexa
listOfFiles1{indexa,2} = 1;
elseif i == indexb
listOfFiles1{indexb,2} = 2;
end
end

请先登录，再回答此问题。

采纳的回答

Stephen23
Stephen23 2017-8-17
编辑：Stephen23 2017-8-17
Method one: regexp and convert using subtraction:
>> C = {'9_X_0_a.bmp';'9_X_0_b.bmp';'19_X_0_a.bmp';'19_X_0_b.bmp'};
>> D = regexp(C,'[ab](?=\.bmp)','match','once');
>> C(:,2) = num2cell([D{:}]-'a'+1)
C =
'9_X_0_a.bmp' 1
'9_X_0_b.bmp' 2
'19_X_0_a.bmp' 1
'19_X_0_b.bmp' 2
Method two: regexprep:
>> C = {'9_X_0_a.bmp';'9_X_0_b.bmp';'19_X_0_a.bmp';'19_X_0_b.bmp'};
>> C(:,2) = regexprep(C,{'.*a\.bmp$','.*b\.bmp'},{'1','2'}) % as string
C =
'9_X_0_a.bmp' '1'
'9_X_0_b.bmp' '2'
'19_X_0_a.bmp' '1'
'19_X_0_b.bmp' '2'
or as double:
D = regexprep(C,{'.*a\.bmp$','.*b\.bmp'},{'1','2'});
C(:,2) = num2cell(str2double(D));

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Characters and Strings 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by