Iteration Without the Implementation of Loops

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BM 2017-8-24

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/353971-iteration-without-the-implementation-of-loops

编辑： BM 2017-8-31

I am interested in being able to run this particular code using i as the iterating vector. While this can easily be accomplished using a for-loop, I would like to do this without using loops of any kind. Essentially what I want is for the vector q to contain all ten values of F when q is solved for a given i-value. The issue currently is that F does not take any value of i, so I am left with an empty x-matrix in the end. I want to iterate for each value of i in the vector, but without using loops. Does anybody have any suggestions?

   %%%Test program
%%Clear variables
close all; 
clear all;
clc;
%%Definitions
syms q
x = [];
i = 1:10;
F = i - 2*q == 0;
solq = solve(F,q);
x = (x,solq)

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BM 2017-8-31

编辑：BM 2017-8-31

在 MATLAB Online 中打开

I tried to adapt this base program to my needs, but I am running into an issue. In my particular program I have my function F dependent on other functions. Would you have suggestions on how to incorporate the same idea if the program was modified to include

q = sym('q',[1,10]);
i = 1:10;
M = @(q) tan(q)/(1+sin(7*q))
N = log(M(q))
F = i - 2*q*N == 0;
solq = solve(F,q)

I obtain the same errors in this program that I do in my actual program, and would appreciate understanding a little more why this is the case. If I solved F via for-loops, everything works. Thanks for your time.

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Answer 1

John D'Errico 2017-8-24

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/353971-iteration-without-the-implementation-of-loops#answer_279140

编辑：John D'Errico 2017-8-24

在 MATLAB Online 中打开

q = sym('q',[1,10]);
i = 1:10;
F = i - 2*q == 0;
solq = solve(F,q)
solq = 
  struct with fields:
       q1: [1×1 sym]
       q2: [1×1 sym]
       q3: [1×1 sym]
       q4: [1×1 sym]
       q5: [1×1 sym]
       q6: [1×1 sym]
       q7: [1×1 sym]
       q8: [1×1 sym]
       q9: [1×1 sym]
      q10: [1×1 sym]
solq.q3
ans =
3/2

I suppose you could use an implicit loop too, in the form of cellfun. But the above works.

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Adam 2017-8-25

That's not a command, that's just the output from the previous command, in the command window.

BM 2017-8-29

Yeah, I realized that after when I arrived at the chapter (in a reference book) that dealt with such information. Sorry for my confusion. Thanks again!

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