Speed up nested for loops

2012 4 13
1 个回答
2 次查看（30 天）

0 个投票

I am trying to speed up the code below. Are there any suggestions on how I could make it faster? Thanks!
%A=ones(192,64); %example matrix
%B=ones(192,64); %example matrix
Bpad=padarray(B,[11 11],0,'both');
c=zeros(1,529);
jcount=1;
for i=-11:11
for j=-11:11
c(jcount)=sum(sum(A.*conj(Bpad(12+i:end-11+i,12+j:end-11+j))));
jcount=jcount+1;
end
end

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回答（1 个）

Andrei Bobrov
Andrei Bobrov 2012-4-13

1 个投票

c0 = conv2(B,A);
c = reshape(c0(2:end-1,2:end-1)',1,[]);
OR
c0 = conv2(Bpad,A,'valid');
c = reshape(c0',1,[]);

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Meral
Meral
2012-4-13

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