How to set which variable to update in an iterative loop?

3 次查看（过去 30 天）
Valerio Cittadini
回答： Anh Tran 2017-9-8
Hello, I have a couple of problems with my Matlab code. I have to set an iterative loop for the variable 'a_D1(z)'. 'a_D1(z)' is an input for a procedure that ends with a result, the one called 'c_x_av_D1(z)' in the code. But there is not an explicit function to relate them. Then I have another quantity, the one called 'c_x_av_mom_D1(z)', that can be explicitly expressed as a function of 'a_D1(z)'. Basically I have to iterate, updating the value of 'a_D1(z)', so that those 2 quantities are equal. Thank you.
a_D1(z)=0.1
.
.
.
.
.
.
.
.
.
.
V_D1(z)=(1-a_D1(z))*V_0
.
.
.
.
.
V_E1(z)=(1-2*a_D1(z))*V_0
.
.
.
.
c_x_av_D1(z)=F_x_av_D1(z)/(1/2*rho*V_0^2*A_d(z))
.
.
.
.
.
.
c_x_av1_D1(z)=4*a_D1(z)*(1-a_D1(z))
  4 个评论
显示 2更早的评论
Valerio Cittadini
Valerio Cittadini 2017-9-6
It is difficult to explain, I admit. Basically those c_x are the same quantity, but calculated with two different approaches, and that's why I called it in two different ways (c_x_av e c_x_av_mom). The first is calculated through a long procedure whose input is that 'a_D1', but there's no direct relation between them. The second can be calculated directly as a function of 'a_D1'. I have to find the value of 'a_D1' that makes the two equal.
Valerio Cittadini
Valerio Cittadini 2017-9-6
Sorry, the two ways I called the quantity are c_x_av_D1 e c_x_av1_D1.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Anh Tran
Anh Tran 2017-9-8
HI Valerio,
My understanding is you just want to find a value of 'a_D1(z)' that makes 'c_x_av_D1' and 'c_x_av1_D1' have equal. You may use a 'while' loop which increases a_D1(z) by a small step size each iteration and terminates when the difference is equal to zero or less than a tolerance. 2 numbers can rarely be exactly equal because of floating-point representation accuracy, so I would suggest setting up a tolerance for their difference. You may need to change step_size and tolerance for your application (might result in an infinite loop if not set carefully along with your initial guess of a_D1). Good luck!
step_size = 0.0001;
tolerance = 0.001;
while terminate ~= 1
a_D1(z) = a_D1(z) + step_size; % increment a_D1(z) with small step_size
% calculate c_x_av_D1
% calculate c_x_av1_D1
if abs(c_x_av_D1 - c_x_av1_D1) < tolerance
terminate = 1; % terminate the while loop
end
end

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by