t=a:h:b;

Question

Mos_bad 2017-9-8

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编辑： James Tursa 2017-9-9

I need to code an iteration for the below algorithm:

 % a,h,b,s are constants. 
t=a:h:b;y(0)=s;
    f(k)(x,t)=t(k)+y(k);
    y(k+1)=y(k)+h*f(k);

please help me how to use for loop for this iteration.

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James Tursa 2017-9-8

编辑：James Tursa 2017-9-8

I assume that the statement y(0)=s is meant to imply that the initial value of y at the initial value of t (which is "a" in this case) is "s"?

This is just numerical integration using the Euler method.

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Answer 1

James Tursa 2017-9-8

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/355797-t-a-h-b#answer_280827

编辑：James Tursa 2017-9-9

在 MATLAB Online 中打开

An outline of the loop:

s = whatever
a = whatever
b = whatever
h = whatever
y = zeros(size(t));
y(1) = s;
for k=1:numel(t)-1
    f = ________;  % <-- you fill the blanks in based on your formula from above
    y(k+1) = _______;  % <-- you fill the blanks in based on your formula above
end

If you want to save each of the derivative values, then you can use f(k) in the loop instead of just f. (And also initialize f = zeros(size(t)) prior to the loop)