Methods to fix values to two decimals

5 次查看(过去 30 天)
Does anyone know the most efficient way to fix values to two significant figures?
I am trying to proof a calculations which initially has the calculated values to two significant figures and then has the final values to 7 significant figures.
When researching I found a MatLab answer stating that you can not fix "binary floating point arithmetic" https://au.mathworks.com/matlabcentral/answers/16882-how-to-round-the-decimal-point
Does MatLab cater for fixed point instead of just floating points?

采纳的回答

Walter Roberson
Walter Roberson 2017-9-12
编辑:Walter Roberson 2017-9-12
You can use the Fixed Point Toolbox.
You can also use the Symbolic Toolbox, but only if you convert the values into ratios, such as converting 0.23 to 23/100 (which sym() can do automatically for you.) If you use symbolic floating point numbers then there are situations where the calculation could be done in binary with the inexact representation problems you have heard about already.
When doing calculations to such limited precision, you need to think carefully about whether you want to round values or truncate values, and if you do want to truncate values, do you want to truncate towards 0 or do you want to truncate towards negative infinity ? For example if 0.236 is rounded towards 0 or negative infinity then that would become 0.23, but if -0.236 is rounded towards 0 that would be -0.23 whereas rounding towards negative infinity would be -0.24
  3 个评论
Walter Roberson
Walter Roberson 2017-9-12
Are you certain that is what you want? Consider -0.954 and -0.955 . For -0.954 the third decimal place < 5 so you want it to round down, which would be to -0.96 . For -0.955 the third decimal place is not < 5 so you want it to round up, which would be to -0.95 . This is a rounding scheme I have ever seen in use!

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by