How to create a checkerboard matrix without inbuilt function.
显示 更早的评论
I just want to write this matrix, but want to do it using for loops
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
8 个评论
Riley Smith
2017-9-12
Stephen23
2017-9-12
@Riley Smith: so try both of them. What is stopping you from trying things out? MATLAB does not explode if your first attempt does not work.
Adam
2017-9-12
This is one of those problems where there is a vast number of different ways to try it. Many that give the right answer and many that give the wrong answer, but command line testing is free. My first attempt yielded the wrong answer as I forgot that the value at the end of a column is equal to that at the start of the next column. But a little tweak soon fixes those problems and experimenting is fun and good for learning.
James Tursa
2017-9-12
If you get stuck, or just want to see how others have done this:
Rik
2017-9-12
Also, the criterion restricting the use of builtins makes it harde to answer this. It is very difficult to define what counts as a builtin and what doesn't, as that quickly devolves into not being able to use Matlab at all (+ is a builtin as well).
You can also use
abs(sin(...)) or abs(cos(...))
with the proper arguments.
James Tursa
2017-9-12
Using the sin function for this would be a sin ...
I had missed this comment ... ;-)
It's one of the rare cases where using a cos would be a sin too ..
0.5-(-1).^((1:n)+(1:n).')/2
or
a = 1 : n ;
a + a.' == 1
采纳的回答
Joseph Cheng
2017-9-12
There are much easier ways to do this than nested for loops, reshape is readily available. if you must do it with for loops you want to start off with the template
for Rind=1:Nrows
for Cind=1:Ncols
Checkerboard(Rind,Cind) = ___;%what condition of Rind and Cind gives you the checker board pattern.
%start with the first row what makes a 1 appear when Rind==1 and Cind=a number.
%then think of the sigificant difference between Rind==1 and Rind==2.....
end
end
更多回答（4 个）
Sangam K
2017-11-25
%Hope this helps you.
function a = checkerboard(n)
a = zeros(n);
for i = 1:n
for j = 1:n
if (i == j)
a (i, j) = 0;
elseif (mod(j, 2) == 0) && (mod(i,2) == 0)
a(i,j) = 0;
elseif (mod(j, 2) == 0) || (mod(i,2) == 0)
a(i,j) = 1;
end
end
end
end
Jan Siegmund
2020-5-21
For an even sized checkerboard:
rows = 6;
cols = 4;
normal = repmat(eye(2,'logical'),[rows/2 cols/2]);
% or
inverted = repmat(~eye(2,'logical'),[rows/2 cols/2]);
Mendi
2020-9-5
It is more natural to use modulus on meshgrid:
[iX,iY] = meshgrid(1:8,1:8);
Mask=mod(iX+iY,2);
2 个评论
Bruno Luong
2020-9-5
One liner variant
mod((1:8)+(1:8)',2)
Mendi
2020-9-6
Yeap. The one liner is better.
Bruno Luong
2020-9-5
编辑：Bruno Luong
2020-9-5
Two more methods
toeplitz(mod(0:7,2))
or for even size
kron(ones(4),[0 1;1 0])
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