Trying to plot function

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Ryan Elway
Ryan Elway 2017-9-13
评论： Ryan Elway 2017-9-13
I have the function y = (x+2)^2/(3x+1) over the range 1=<x=<2 and when I graph it the plot stops at 1 on the x axis so when I put in the range into the data bounds it doesn't show up. I'm not sure if I'm typing the function out wrong or what I'm doing.
here is what I have:
clc;
x = linspace(0,1,100);
y = (x+2)^2./(3*x+1);
plot(x,y);
I've tried different values for the linspace, putting a "." before the ^2
Any help would be appreciated

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采纳的回答

KSSV
KSSV 2017-9-13
x = linspace(0,1,100);
y = (x+2).^2./(3*x+1);
plot(x,y);
REad about element by element operation...use .^ instead of ^.
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KSSV
KSSV 2017-9-13
The plot is stopping on xaxes at 1, because you have provided x values till 1 only.
See this:
x = linspace(0,100,1000); % change limits here
y = (x+2).^2./(3*x+1);
plot(x,y);
Ryan Elway
Ryan Elway 2017-9-13
Thank you again I actually figured it out I changed the linspace part to
x = linspace(0,2,100);
thanks again, my mistake

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更多回答（1 个）

Aryan Safaie
Aryan Safaie 2017-9-13
Dear Ryan,
Are you sure that adding a '.' before the '^2' doesn't help? When I try the following line when calculating y, I get a plot that looks correct:
y = (x+2).^2./(3*x+1);
Best,
-aryan
  1 个评论
Ryan Elway
Ryan Elway 2017-9-13
I had x = linspace(0,1,100) instead of linspace(0,2,100) thank you for the help though!

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