Algorithm conversion with code generation
显示 更早的评论
Hi all, I am working on an algorithmic function and I'd like to convert it into C. Code as stated below,
ImgR= Input(:,:,1); % Red colour channel.
ImgG= Input(:,:,2); % Green colour channel.
ImgB= Input(:,:,3); % Blue colour channel.
However while converting, I ran into an error stating - "Index expression out of bounds. Attempted to access element 2. The valid range is 1-1." How can I resolve this issue? Thanks!
回答（1 个）
John D'Errico
2017-9-16
0 个投票
You don't have a color image. You have a purely grayscale image. So trying to extract the red green and blue planes is waste of time.
So you need to convert the grayscale image to three channel color, most simply done by replicating the gray image into three color planes, or use an appropriate tool to do a better job. Or work with a color image to start with.
3 个评论
Chan KitHoe
2017-9-16
Walter Roberson
2017-9-17
if ndims(Input) > 2
ImgR= Input(:,:,1); % Red colour channel.
ImgG= Input(:,:,2); % Green colour channel.
ImgB= Input(:,:,3); % Blue colour channel.
else
ImgR = Input;
ImgG = Input;
ImgB = Input;
end
Image Analyst
2017-9-17
Even though MATLAB is case sensitive, I don't think it's a good idea to name variables after built-in functions, even if the capitalization is different.
类别
在 帮助中心 和 File Exchange 中查找有关 MATLAB Coder 的更多信息
2017-9-16
2017-9-17
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
