Print numbers on an array that have a unique row and column

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Shawn Blancett
Shawn Blancett 2017-9-16
评论： Shawn Blancett 2017-9-16
The code I wrote can print 1's on a unique column but can be on the same row. How could I get it to have a unique row?
for k=1:N % Loops N times
random = randi([1,N]); % Chooses a random number between 1 and board size
X(k,random) = 1; % Places a 'queen' on a random column
end

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采纳的回答

Jan
Jan 2017-9-16
编辑：Jan 2017-9-16
Perhaps you want:
index = randperm(8, 8);
X = zeros(8, 8);
for k = 1:8
X(k, index(k)) = 1;
end
0 0 0 0 0 0 1 0
0 1 0 0 0 0 0 0
0 0 0 0 0 0 0 1
0 0 0 0 0 1 0 0
0 0 0 0 1 0 0 0
1 0 0 0 0 0 0 0
0 0 0 1 0 0 0 0
0 0 1 0 0 0 0 0
Alternatively without a loop:
X = zeros(8, 8);
X(sub2ind([8,8], 1:8, randperm(8, 8))) = 1

更多回答（2 个）

Image Analyst
Image Analyst 2017-9-16
Try this:
X = zeros(8, 8); % Initialize
rc = randi([1,8], 1, 2) % One location on the board.
X(rc(1), rc(2)) = 1 % Assign a queen to that square
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Jan
Jan 2017-9-16
I still don't get it: Do you mean a single 1 in each row and in each column?
Shawn Blancett
Shawn Blancett 2017-9-16
If the board was NxN I want N amount of 1's the board, that have a unique row and column , so no 1 shares a column or row with another 1

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Walter Roberson
Walter Roberson 2017-9-16
X = zeros(N, N);
available = 1 : N;
for k=1:N % Loops N times
ridx = randi(length(available));
random = available(ridx);
available(ridx) = [];
X(k,random) = 1; % Places a 'queen' on a random column
end

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