Hello Ano,
If you were to do this:
x = 0:1:10;
y = sin(x);
intsinxdx = sum(y);
Then this would be a valid approximation of the integral. Technically, it would be the left Riemann sum integrating from 0 to 11, with step-size 1. This is really the key part, because if you were to try this:
x = 0:0.1:10;
y = sin(x);
intsinxdx = sum(y);
then this would not be accurate. That is because to approximate the integral, you have to multiply the height by the width of the given rectangle. It only worked in the previous case because the width of the rectangles were 1.
However, if you simply use the integral function, that uses an adaptive quadrature approximation. So that may be your best-bet for a quick implementation of an approximate integral.
-Cam
