How to get rid of repeating values inside an array

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Rokki
Rokki 2017-9-19
编辑： Andrei Bobrov 2017-9-21
I have a matrix
a=[1 2 3 3 4 4 5];
I want to get rid of values 3 and 4 as they are repeating so that the output becomes
b=[1 2 5]

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采纳的回答

José-Luis
José-Luis 2017-9-19
编辑：José-Luis 2017-9-19
b = a(sum(bsxfun(@eq,a,a'))==1)
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José-Luis
José-Luis 2017-9-19
编辑：José-Luis 2017-9-19
My pleasure.
Please keep in mind that this is inefficient for large arrays though. Just using unique() should take you where you need to go.

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更多回答（1 个）

Andrei Bobrov
Andrei Bobrov 2017-9-19
编辑：Andrei Bobrov 2017-9-21
v = unique(a);
b = v(histcounts(a,[v(:);v(end)+eps]) == 1);
or
v = unique(a);
b = v(histc(a,v) == 1);
or
aa = sort(a);
t = diff(aa);
b = aa([1 t] & [t 1]);
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José-Luis
José-Luis 2017-9-19
histcounts() was introduced with R2014b. You don't need it though. unique() is enough. Andrei was giving you two alternatives.

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