0 个投票

Hello, I am trying to extract every 2000 rows in a 20000 row column and place each extracted matrix into a separate column to create a 2000x10 matrix. However, I am getting an error: In an assignment A(:) = B, the number of elements in A and B must be the same. Any ideas?
Test=zeros(2000,10);
for w=1:10
Test(w)=zt3((2000.*(w-1))+1:2000.*w,1:1)
end

请先登录，再回答此问题。

 采纳的回答

OCDER
OCDER 2017-9-19
编辑：OCDER 2017-9-19

0 个投票

Is this what you want to do?
zt3 = [1:20000]'; %assuming zt3 is a 20000x1 matrix
Test = reshape(zt3, 2000, 10);
%Takes row 1:2000, 2001:4000, etc and stores each in a column in a new matrix.

4 个评论
显示 2更早的评论 隐藏 2更早的评论

Francis Herman
Francis Herman 2017-9-19
Not exactly. I would like to take all values in each 2000 row intervals and place them into a new matrix. So rows 1-> 2000 goes into the first column of the new matrix; rows 2001->4000 goes into the second column of the new matrix; etc.
OCDER
OCDER 2017-9-19
Oh, I see. For this case, maybe reshape is the better option, assuming dzt is a 20000x1 matrix. I changed the answer above.
Francis Herman
Francis Herman 2017-9-19
Yes, this solved my problem. Thank you very much for the help.
OCDER
OCDER 2017-9-19
You're welcome! Oh, I should have explained why your code didn't work. You were doing Test(w) = zt3(1:2000), but Test(w) is 1 element while zt3(1:2000) is 2000 elements. The elements must match in input and output. To make the for loop work, you'd have to fix it as below:
Test = zeros(2000, 10);
for w = 1:10
Test(:, w) = zt3(2000*(w-1)+1:2000*w, 1);
%Fill all row " : " for column number w in Test
end

请先登录，再进行评论。

更多回答（1 个）

Walter Roberson
Walter Roberson 2017-9-19

0 个投票

T = mat2cell(zt3, 2000*ones(1,size(zt3,1)/2000), size(zt3,2));

类别

在 帮助中心 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by