How to add some values between two points？

Question

HONG CHENG 2017-9-20

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https://ww2.mathworks.cn/matlabcentral/answers/357465-how-to-add-some-values-between-two-points

评论： Image Analyst 2017-9-20

采纳的回答： HONG CHENG

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Dear everyone, Now I have some coordinates pairs and I want to add more points in the area.

For example, If I have the dataset

A = [1,2;2,2;1,3;2,3]

I want to get the matrix

B = [1, 2 ; 1.1, 2; 1, 2.1 ;1.1, 2.1; ..... ; 1.9, 2.9; 2.9, 3; 2, 2.9 ; 2, 3  ]

Thanks a lot

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Answer 1

HONG CHENG 2017-9-20

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In here, I didn't use any special function. but the result looks not bad

Xmin = 1;
Ymin = 2;
Xmax = 2;
Ymax = 3;
step = 0.1;
step_1 = 1/0.1;
K = (Xmax-Xmin)*(Ymax-Ymin)*step_1*step_1;
Co = zeros(K,2);
n_Co = 1;
for i = Xmin:step:Xmax
    for j = Ymin:step:Ymax
        Co(n_Co, 1) = i;
        Co(n_Co, 2) = j;
        n_Co = n_Co+1;
      end
  end

My result is in the following

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Image Analyst 2017-9-20

Except that's not what you originally asked for. Originally you had the first column increasing every row.

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Answer 2

Walter Roberson 2017-9-20

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编辑：Walter Roberson 2017-9-20

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r = linspace( min(A(:,1)), max(A(:,1)), 11 );
c = linspace( min(A(:,2)), max(A(:,2)), 11 );

11 is needed instead of 10 because you need to include the final value.

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HONG CHENG 2017-9-20

Thanks for your quick answer. And now we get the linspace for X and Y, but I need a matrix of them as the picture shows, I want to get the values as the blue block area shows~~~

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Answer 3

Image Analyst 2017-9-20

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How about this:

n = 20 % Whatever...
A = [1,2;2,2;1,3;2,3]
% Make new linearly interpolated array.
A2 = imresize(A, [n, 2])
A2 = A2(3 : end-2,:)

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HONG CHENG 2017-9-20

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Thanks for your answer.

And I have tried your method, but the result looks a little strange

876250000000000  2
886250000000000  2
906250000000000  2
936249999999999  2
976250000000000  2
02981250000000  1.99881250000000
11493750000000  1.99043750000000
22656250000000  1.97656250000000

they are not uniform

Now I write my own code in the following answer.maybe there is a better method

Thanks a lot

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