"index exceeds matrix dimension" problem
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Hello,
When I run the code below without an r-loop, I don't have any problems. But when I try to run it like as what is written below, MATLAB is giving "Index exceeds matrix dimension" error. Is there anyone who can help me with this? Thanks in advance!
heye=eye(length(b0),length(b0));
for t=1:length(b0)
heye(t,t)=delt(t);
end
betas1=zeros(length(b0),length(b0));
for r=1:length(b0)
betas1(:,r)=b0;
end
betas1=betas1+heye;
lf1=zeros(numobs,length(b));
%keyboard;
for r=1:length(b0)
b0=betas1(:,r);
A=zeros(numobs,1);
B=zeros(numobs,1);
for i=1:numobs
if c(i)==1
funnon=@(x)exp(-x*b0(1)*t(i))./x;
qnon=integral(funnon,1,1+b0(2)*1);
if qnon~=0
B(i)=qnon;
else
B(i)=0.0000000000000000000000000000000000000000000000001;
end
elseif c(i)==2
funint=@(x)(exp(-x*b0(1)*t1(i))-exp(-x*b0(1)*t2(i)))./x.^2;
qint=integral(funint, 1, 1+b0(2)*1);
if qint~=0
B(i)=qint;
else
B(i)=0.0000000000000000000000000000000000000000000000001;
end
%B(i)=qint;
else
funr=@(x)exp(-x*b0(1)*t(i))./x.^2;
qr=integral(funr, 1, 1+b0(2)*1);
if qr~=0
B(i)=qr;
else
B(i)=0.0000000000000000000000000000000000000000000000001;
end
%B(i);
end
end
for i=1:numobs
if c(i)==1
y(i) = log(b0(1))+log(1+b0(2)*1)-log(b0(2)*1)+log(B(i));
A(i)=y(i);
elseif c(i)==2
y(i)=log(1+b0(2)*1)-log(b0(2)*1)+log(B(i));
A(i)=y(i);
else
y(i)=log(1+b0(2)*1)-log(b0(2)*1)+log(B(i));
A(i)=y(i);
end
end
lf1(:,r)=A;
end
4 个评论
KSSV
2017-9-21
Without specifying the line number of error and having no clue on what are the variables and their dimensions, how you expect us to help you?
selin
2017-9-21
Walter Roberson
2017-9-21
t is not a 35781 x 1 vector. You have
for t=1:length(b0)
heye(t,t)=delt(t);
end
which is overwriting t with a scalar
selin
2017-9-21
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