0 个投票

I have 3D matrix A=50x60x180 and I want subtract B=50x60 to get same size C=50x50x180? Can anybody use for loop to do this operation?

2 个评论
显示 无 隐藏 无

John Chilleri
John Chilleri 2017-9-21
C = zeros(50,60,180);
for i = 1:180
C(:,:,i) = A(:,:,i) - B;
end
Is this what you mean?
Andrei Bobrov
Andrei Bobrov 2017-9-21
?
size of the C -> [50x 50 x180]? Maybe - [50x 60 x180]

请先登录，再进行评论。

请先登录，再回答此问题。

 采纳的回答

Andrei Bobrov
Andrei Bobrov 2017-9-21

1 个投票

C = A - B;
or
C = bsxfun(@minus,A,B);

2 个评论
显示 无 隐藏 无

Walter Roberson
Walter Roberson 2017-9-21
The first of those works in R2016b or later but not in earlier versions.
Andrei Bobrov
Andrei Bobrov 2017-9-21
Walter! I am agree with you!

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by