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I need to display the max value in this function.

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Kevin Smith
Kevin Smith 2017-9-25
评论： Stephen23 2017-10-23
I have been working on a script for a function 'collatz' and I originally made it way more complex than it needed to be. I've managed to simplify it down to this:
function [s,m]=collatz(num)
cnt=0;
m=-inf;
while num>1
cnt=cnt+1;
if mod(num,2);
num=num*3+1;
else
num=num/2;
end
end
The only problem I have is getting 'm' to represent the maximum value. The 's' displays the number of steps it takes to complete the while loop. That part of the script works fine. Example of what I would need: >>[s,m]=collatz(3) %which would take 7 steps in my function with a max value of 16. s= 7 m= 16

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采纳的回答

KSSV
KSSV 2017-9-25
function [s,m]=collatz(num)
cnt=0;
X = zeros([],1) ;
while num>1
cnt=cnt+1;
if mod(num,2)
num=num*3+1;
X(cnt) = num ;
else
num=num/2;
X(cnt) = num ;
end
end
m = max(X) ;
fprintf('Maximum values is:%f\n',m)

更多回答（1 个）

Stephen23
Stephen23 2017-9-25
编辑：Stephen23 2017-9-25
Rather than enlarging the array on each iteration as KSSV showed (and in general is a bad practice that should be avoided), you should simply call max on each iteration, which makes the code simpler too:
function [cnt,mxv] = collatz(num)
cnt = 0;
mxv = 0;
while num>1
cnt = cnt+1;
if mod(num,2) % odd
num = num*3+1;
else % even
num = num/2;
end
mxv = max(mxv,num);
end
end
And tested:
>> [s,m] = collatz(3)
s =
7
m =
16

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