Vectorization of this loop

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The following loop calculates the distance and angle values of every location from a point and stores in arrays named Radius and theta. This loop is called nearly 3600 times in the code. This loop is effecting the performance of the code. Please suggest some ways to vectorise this loop.
xwidth and ywidth varies from 500 to 750. So, memory needed is also very high. Please suggest ways to decrease the memory needed.
x1=0;
y1=1;
inj_x=round(xwidth/2.0);
inj_y=round(ywidth/2.0);
Radius=zeros(ywidth,xwidth);
theta=zeros(ywidth,xwidth);
for r=1:ywidth
for c=1:xwidth
x2=r-inj_y;
y2=c-inj_x;
Radius(r,c)=(x2^2+y2^2)^.5;
theta(r,c)=mod(atan2(x1*y2-x2*y1,x1*x2+y1*y2),2*pi);
end
end
Thanks in advance

采纳的回答

Andrei Bobrov
Andrei Bobrov 2012-4-18
in your case
r = (1:ywidth).' - round(ywidth/2);
c = (1:xwidth) - round(xwidth/2);
Radius = bsxfun(@hypot,r,c);
theta = mod(bsxfun(@atan2,-r,c),2*pi);
  1 个评论
Dilunath Hareendranath
Thanks andrei.. This code is taking only 0.09 seconds to process.. whereas previous code was taking 2.8 seconds.

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更多回答(2 个)

Honglei Chen
Honglei Chen 2012-4-18
x1=0;
y1=1;
inj_x=round(xwidth/2.0);
inj_y=round(ywidth/2.0);
[x2,y2] = ndgrid((1:ywidth)'-inj_y,(1:xwidth)'-inj_x);
Radius=(x2.^2+y2.^2).^.5;
theta=mod(atan2(x1.*y2-x2.*y1,x1.*x2+y1.*y2),2*pi);
  1 个评论
Dilunath Hareendranath
Thanks Honglei Chen for answering. This code is also taking less time.

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Jan
Jan 2012-4-18
For a fair speed comparison cleanup the loops:
  • move all repeated calculation outside
  • SSQRT() is faster than ^0.5
twoPi = 2 * pi;
for r = 1:ywidth
x2 = r - inj_y;
x2_2 = x2 * x2;
x1x2 = x1 * x2;
y1x2 = y1 * x2;
for c = 1:xwidth
y2 = c-inj_x;
Radius(r,c) = sqrt(x2_2 + y2^2);
theta(r,c) = mod(atan2(x1*y2 - y1x2, x1x2 + y1*y2), twoPi);
end
end
Perhaps a partial vectorization is fastest:
twoPi = 2*pi;
for c = 1:xwidth
y2 = c-inj_x;
x2 = transpose(1-inj_y:ywidth - inj_y);
Radius(:,c) = sqrt(x2.^2 + y2^2);
theta(:,c) = mod(atan2(x1*y2-x2*y1, x1*x2+y1*y2), twoPi);
end
And fully vectorized:
x2 = transpose(1 - inj_y:ywidth - inj_y);
y2 = 1 - inj_x:xwidth - inj_x;
Radius = sqrt(bsxfun(@plus, x2 .^ 2 + y2 .^ 2);
k1 = bsxfun(@minus, x1 * y2, y1 * x2);
k2 = bsxfun(@plus, x1 * x2, y1 * y2);
theta = mod(bsxfun(@atan, k1, k2), 2*pi);
And if x1 and y1 are really fixed to 0 and 1 this can be simplified.

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