help completeing Alphabetical matrix problem

Question

Hayden O'Neil 2017-10-7

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回答： Walter Roberson 2017-10-8

Write Matlab code that creates a new 5x10 matrix that creates an alphabetical matrix that displays the letter of the matrix that has the HIGHEST value of the 3 matrices A,B,C from Problem #1 on an element by element basis

%Question 3 
A = [12 3 56 78 3 4 5 10 91 21; 16 18 3 5 7 17 4 7 10 11;
    2 4 6 8 10 12 10 6 3 19; 1 22 8 9 12 7 17 5 8 10; 
    7 6 2 1 45 8 17 8 9 16];
B = [16 81 18 3 5 7 9 12 9 11; 0 2 3 7 82 6 9 15 12 10; 
    7 4 1 1 8 7 15 43 11 17; 8 3 1 0 1 0 4 5 9 16; 
    7 6 2 1 45 8 17 8 9 16];
C = [6 7 68 24 13 2 8 16 22 2; 67 13 4 5 9 11 16 12 22 1;
    13 14 15 9 64 41 12 11 10 3; 2 0 1 4 6 1 6 2 3 3;
8  5 6 4 2 5 60 25 13 3];
m = max( max (A,B), C);
vars = {'A','B','C'};
mask1 = m == A;
mask2 = m == B;
mask3 = m == C;
which_one = cell(size(m));
which_one(mask1) = vars(1);
which_one(~mask2) = vars (2);

Your output should look like this :

OutputMatrix = [B B C A C B B C A A;C A C B .. .. .. .. .. ..; .. .. .. .. .. .. .. .. .. ..;

this is what I have so far up my output matrix is incorrect.

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Answer 1

Kian Azami 2017-10-7

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https://ww2.mathworks.cn/matlabcentral/answers/360175-help-completeing-alphabetical-matrix-problem#answer_284730

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If your question is understood correctly, by the following code you can create the Alphabetical matrix that you need:

clc
clear all
A = [12 3 56 78 3 4 5 10 91 21; 16 18 3 5 7 17 4 7 10 11;...
  2 4 6 8 10 12 10 6 3 19; 1 22 8 9 12 7 17 5 8 10; 7 6 2 1 45 8 17 8 9 16];
B = [16 81 18 3 5 7 9 12 9 11; 0 2 3 7 82 6 9 15 12 10;...
  7 4 1 1 8 7 15 43 11 17; 8 3 1 0 1 0 4 5 9 16; 7 6 2 1 45 8 17 8 9 16];
C = [6 7 68 24 13 2 8 16 22 2; 67 13 4 5 9 11 16 12 22 1;...
  13 14 15 9 64 41 12 11 10 3; 2 0 1 4 6 1 6 2 3 3; 8  5 6 4 2 5 60 25 13 3];
ABC = {};
for jj = 1:5
  for hh = 1:10
      X = max([A(jj,hh),B(jj,hh),C(jj,hh)]);
      if X == A(jj,hh)
          ABC{jj,hh} = 'A';
      elseif X == B(jj,hh)
          ABC{jj,hh} = 'B';
      elseif X == C(jj,hh)
          ABC{jj,hh} = 'C';
      end
  end   
end
disp(ABC)