Switch case simple mistake

2017 10 8
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更新时间：2017 10 8
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Hi, why doesnt 'works' show when i run this? Is it because the case has to be the switch input?
inStr='d'
switch inStr
case inStr(1)=='d'
outStr='works'
otherwise
'error'
end

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Walter Roberson
Walter Roberson 2017-10-8

0 个投票

case inStr(1)=='d' evaluates inStr(1)=='d', generating the value false or true. That value is then compared to inStr because of switch inStr, and is found to not equal to inStr.
switch inStr(1)
case 'd'

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