What does the error `Error in checkArgsForHandleToPrint` mean?
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What does the error:
Error using checkArgsForHandleToPrint
Handle input argument contains nonhandle values.
Error in checkArgsForHandleToPrint
Error in print>LocalCreatePrintJob (line 97)
handles = checkArgsForHandleToPrint(0, varargin{:});
Error in print (line 38)
[pj, inputargs] = LocalCreatePrintJob(varargin{:});
if possible, how does one fix it too would be nice.
3 个评论
Kalyan
2023-1-25
A=[1,2,3,4,5,6,7,7,7];
c=unique(A)
print(A);
same error
Error using checkArgsForHandleToPrint
Handle input argument contains nonhandle values.
Error in checkArgsForHandleToPrint
Error in print>LocalCreatePrintJob (line 97)
handles = checkArgsForHandleToPrint(0, varargin{:});
Error in print (line 38)
[pj, inputargs] = LocalCreatePrintJob(varargin{:});
回答(2 个)
Nathan Daubenmier
2021-1-22
Try using :
fprintf('Info you are trying to print: %f', data_name);
rather than:
print('Info you are trying to print: %f', data_name);
Hope this helps!
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