Passing function handle to another function and assigning varying number of input arguments to it

1 次查看(过去 30 天)
Hi,
I am trying to write a code in which I need to pass a handle function to another function, let say
function b=myfun1(a)
b=2*a;
end
function b=myfun2(handle_f,a)
b=a*handle_f(a)
end
result=myfun2(@(aa)myfun1(aa),a);
Well, this works perfectly fine. Now let say that I want to decide to vary the number of and type of arguments of myfun1 or use completely different function. How should I write myfun2 to be able to work with any type of function with different number of input arguments and of course same output type?

回答(1 个)

Andrei Bobrov
Andrei Bobrov 2012-4-20
please read about varargin, nargin and varargout, nargout
eg
function b=myfun2(handle_f,varargin)
a = varargin{1};
b=a.*handle_f(varargin{:})
end
on Hossein's comment
myfun2(@(x)myfun3(x,y),a); %here y is defined
myfun2(@(y)myfun3(x,y),a); %here x is defined
myfun2(@(x,y)myfun3(x,y),a,y);
myfun2(@(y,x)myfun3(x,y),a,x);

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