reshaping cell containing double arrays

2017 10 10
3 个回答
更新时间：2017 10 10
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Hi,
I have (as an example) the following cell array:
test =
1×4 cell array
[40×1 double] [40×1 double] [40×1 double] [40×1 double]
I want test to be a 1 x 1 cell, containing the double arrays (from left to right) as one double array of dimension 160 x 1. reshape(test,[160,1]) does not work directly here. What can I do?

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回答（3 个）

KSSV
KSSV 2017-10-10
编辑：KSSV 2017-10-10

1 个投票

test = cell(1,4) ;
for i = 1:4
test{i} = rand(40,1) ;
end
iwant = cell2mat(test) ;
iwant = {iwant(:)} ;

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MiauMiau
MiauMiau 2017-10-10
Is there no quicker way than looping?
Guillaume
Guillaume 2017-10-10
The loop is only to build the demo data.

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Guillaume
Guillaume 2017-10-10

1 个投票

That's because what you want is not reshaping but a concatenation. (The matrices may not be contiguous in memory):
test = [test{:}]

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MiauMiau
MiauMiau 2017-10-10
That is giving me a 40x4 matrix...?!
Guillaume
Guillaume 2017-10-10
编辑：Guillaume 2017-10-10
Oh yes, your vectors are column vectors. Concatenate them vertically then:
test = vertcat(test{:})

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MiauMiau
MiauMiau
2017-10-10

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Guillaume
Guillaume
2017-10-10

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