Plot binary image with all coordinates of points
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I have a matrix with 2 rows:
First is x-coordinate
Second is y-coordinate
How can i plot a binary image with all coordinates of points in that matrix
3 个评论
KSSV
2017-10-12
What data you have as pixel or z data?
Actually, I plot a contour from a blood sample and receive a contour matrix. So, my coordinates don't have natural spacing; I want to count cell by counting closed loop in contour image. Is there any way to do so?
Walter Roberson
2017-10-12
I would recommend a different approach for that.
- quantize the readings according to the contour levels you want.
- replace each array entry by the bin number of the quantized level
- now use regionprops to figure out all of the distinct regions. If you only need to know how many there are, then ask for any simple property, but then look at the size of the returned structure to see how many regions there were.
采纳的回答
Walter Roberson
2017-10-12
If the coordinates are positive integers, then
binary_image = full( sparse( YourMatrix(1, :), YourMatrix(2, :), true ) );
8 个评论
Nguyen Hung
2017-10-12
Walter Roberson
2017-10-12
What result would you like in that case?
Is there a natural spacing, such as if the coordinates might end in .0 or .25 or .5 or .75 giving a natural spacing of 1/4 unit? If there is then you can divide the coordinates by the spacing in order to get integers that can be processed like above.
If there is no natural spacing, do you want to quantize the coordinates, such as if you want to treat anything beween 0.15 and 0.20 as belonging in the slot for .15? Thus getting you an artificial spacing that you can use to determine which pixel to light?
If there is no natural spacing and you do not want to quantize, do you want to do something like have each coordinate pair act as a circle of constant radius around it, and any pixel which in total is more than half covered by touching or overlapping circles is to be treated as lit?
If there is no natural spacing, do you want to light pixels based upon density of points? Perhaps with a denser block lighting a larger block?
... and so on. You need to tell us how you want to determine which pixel(s) are lit given your list of coordinates.
Nguyen Hung
2017-11-11
Image Analyst
2017-11-11
What does it mean to "plot" an image? Do you mean "display" an image, like with imshow()? Or do you want to plot the x coordinates in a line plot or bar chart or something?
Walter Roberson
2017-11-11
x = p(:,1);
y = p(:,2);
minx = min(x);
maxx = max(x);
miny = min(y);
maxy = max(y);
target_rows = 331;
target_cols = 504;
xsteps = linspace(minx, maxx, target_cols+1);
xsteps(end) = inf;
ysteps = linspace(miny, maxy, target_rows+1);
ysteps(end) = inf;
[~, xbin] = histc(x, xsteps);
[~, ybin] = histc(y, ysteps);
dimg = accumarray([ybin, xbin], 1, [target_rows, target_cols]);
bwimg = dimg > 0;
subplot(1,2,1); imshow(dimg); title('density')
subplot(1,2,2); imshow(bwimg); title('occupancy')
Nguyen Hung
2017-11-12
Hélène MACHER
2019-5-31
编辑：Hélène MACHER
2019-5-31
Hello,
Thank you very much for your answer, it's much more faster than whith for loops.
I'm working on a filtering algorithm for point clouds. I create a binary image from a point cloud and I clean this image thanks to several functions available in Matlab.
Then, I would like to go back to the point cloud in other words I would like to find the points corresponding to the white pixels. I manage to do this with for loops but it's quite long. Any idea to do it faster?
Hélène
Walter Roberson
2019-5-31
Along with your binary image create a 2d array in which each value is 0 if the binary is unoccupied, and is the linear index of the original in the point cloud for occupied. Do the processing on the binary image. Then multiply the result binary image by the coordinate array. The nonzero values left are the indices of the original point cloud.
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