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I'm trying to check for a NaN value in an array in if condition expression but the control is not entering inside if condition.

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Bhargav Boddupalli
Bhargav Boddupalli 2017-10-12
评论： KSSV 2017-10-12
For example :
A = [1 2 3 NaN 3 5]; if isnan(A) ~= 0 %... end

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KSSV
KSSV 2017-10-12
A = [1 2 3 NaN 3 5];
idx = isnan(A) ; % all NaN indices at once
for i = 1:length(A)
if isnan(A(i))
fprintf('%d index value is NaN\n',i)
end
end

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