getting first element of each cell array with different sizes
显示 更早的评论
Hi,
I have a 205 x 1 cell with diffferent sizes and I want to extract only the first element of each cell. For example, I have:
[8,14]
[10,14,15]
[9,14]
[5,14] etc till 205
and the result should be:
8
10
9
5.
Thanks a lot!
M.
采纳的回答
>> C = {[8,14];[10,14,15];[9,14];[5,14]};
>> cellfun(@(v)v(1),C)
ans =
8
10
9
5
1 个评论
Stephen23
2017-10-18
And to allow for empty arrays:
>> C = {[8,14];[10,14,15];[9,14];[5,14];[]};
>> idx = ~cellfun('isempty',C);
>> out = zeros(size(C));
>> out(idx) = cellfun(@(v)v(1),C(idx))
out =
8
10
9
5
0
更多回答（2 个）
Christian Keine
2017-10-18
There are at least two possible ways this could be done. First, you could loop through the cell array and extract the first value of each cell. This is, however, probably not the most elegant or fastest solution. The second option is to use cellfun in combination with an anonymous function which extracts only the first value of each cell, which should work faster for large arrays and is easier to read.
To do so, first define the function that should be executed for each cell:
fun = @(x) x(1)
Then apply this function to each cell in the array using cellfun with x being you cell array
firstElement = cellfun(fun,x)
Using your data it would look like this:
x = {[8,14],[10,14,15],[9,14],[5,14]}
fun = @(x) x(1)
firstElement = cellfun(fun,x)
Hope this is helpful.
Daniel Rieger
2019-7-10
编辑：Daniel Rieger
2019-7-10
Hello guys,
what if i only want to obtain the first entry of the first cell?
Or more general: what if i want a specific entry not for each but only for one cell?
I could also use and then cut out the entries that i dont need, but is there a more elegant way?
% N: wanted entry
all_entry = cellfun(@(v)v(1),C)
wanted_entry = all_entry(N)
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