How do I break a complex loop with a multiple-if structure?

Question

GEORGIOS BEKAS 2017-10-18

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/361982-how-do-i-break-a-complex-loop-with-a-multiple-if-structure

编辑： Matt J 2017-10-18

I am writing a code that has the following form:

   for i = 1:size(interiorcolumns,1)
    if interiorcolumns{i}(6) == heightsmatrix(1)
      condition 1
    elseif interiorcolumns{i}(6) == heightsmatrix(2)
      condition 2
    elseif interiorcolumns{i}(6) == heightsmatrix(3)
      condition 3
    elseif interiorcolumns{i}(6) == heightsmatrix(4)
      condition 4
    elseif interiorcolumns{i}(6) == heightsmatrix(5)
      condition 5
    else
      condition 6
    end
    end

When the heightsmatrix, is smaller than six row elements, I want the redundant if statements not to be taken into account. How can I do that?

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Matt J 2017-10-18

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/361982-how-do-i-break-a-complex-loop-with-a-multiple-if-structure#answer_286479

编辑：Matt J 2017-10-18

在 MATLAB Online 中打开

Another way

     for i = 1:size(interiorcolumns,1)
       switch find(  interiorcolumns{i}(6) == heightsmatrix, 1 )
       case 1
          condition 1
       case 2
          condition 2
       case 3
          condition 3
       case 4
          condition 4
       case 5
          condition 5
        otherwise 
          condition 6
       end
    end