How do I break a complex loop with a multiple-if structure?
显示 更早的评论
I am writing a code that has the following form:
for i = 1:size(interiorcolumns,1)
if interiorcolumns{i}(6) == heightsmatrix(1)
condition 1
elseif interiorcolumns{i}(6) == heightsmatrix(2)
condition 2
elseif interiorcolumns{i}(6) == heightsmatrix(3)
condition 3
elseif interiorcolumns{i}(6) == heightsmatrix(4)
condition 4
elseif interiorcolumns{i}(6) == heightsmatrix(5)
condition 5
else
condition 6
end
end
When the heightsmatrix, is smaller than six row elements, I want the redundant if statements not to be taken into account. How can I do that?
采纳的回答
Another way
for i = 1:size(interiorcolumns,1)
switch find( interiorcolumns{i}(6) == heightsmatrix, 1 )
case 1
condition 1
case 2
condition 2
case 3
condition 3
case 4
condition 4
case 5
condition 5
otherwise
condition 6
end
end
更多回答（1 个）
I would just fill the missing elements with NaNs
heightsmatrix(end+1:6)=nan;
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