This assignment writes a 'char' value into a 'double' type.

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tsai kai shung 2017-10-19

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/362098-this-assignment-writes-a-char-value-into-a-double-type

评论： Rik 2017-10-19

if true
 function word  = fcn(L,Ne,re,templates)
word = [];
for n=1:Ne
      [r,c] = find(L==n);
      % Extract letter
      n1=re(min(r):max(r),min(c):max(c));  
      % Resize letter (same size of template)
      img_r=imresize(n1,[42 24]);
       comp=[ ];
      for n=1: 24 : 240
          sem=Corr2(templates(1:42,n:n+23),img_r);
          comp=[comp sem];
      end
      vd=find(comp==max(comp));
      %*-*-*-*-*-*-*-*-*-*-*-*-*-
      if vd==1
          letter='1';
      elseif vd==2
          letter='2';
      elseif vd==3
          letter='3';
      elseif vd==4
          letter='4';
      elseif vd==5
          letter='5';
      elseif vd==6
          letter='6';
      elseif vd==7
          letter='7';
      elseif vd==8
          letter='8';
      elseif vd==9
          letter='9';
      else
          letter='0';
      end

        % Letter concatenation

        word = [word letter];
end

end end i use the matlab code on simulink but show the error!

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Answer 1

Rik 2017-10-19

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/362098-this-assignment-writes-a-char-value-into-a-double-type#answer_286602

在 MATLAB Online 中打开

You should change various things. See the version below.

function word  = fcn(L,Ne,re,templates)
%initializing to empty char can be done with word='';
word = char(zeros(1,Ne));
for n=1:Ne
    [r,c] = find(L==n);
    % Extract letter
    n1=re(min(r):max(r),min(c):max(c));
    % Resize letter (same size of template)
    img_r=imresize(n1,[42 24]);
    comp=zeros(1,10);%explicit pre-allocation
    for m=1: 24 : 240%conflicted index, also changed to m on next line
        sem=Corr2(templates(1:42,m:m+23),img_r);
        comp((m+23)/24)=sem;
    end
    vd=find(comp==max(comp));
    %*-*-*-*-*-*-*-*-*-*-*-*-*-
    letter=sprintf('%d',mod(vd,10));
    %mod(vd,10) keeps 1:9 the same and changes 10 to 0.
      % Letter concatenation
      word(n) = letter;
  end

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tsai kai shung 2017-10-19

this function is matlab function on simulink so simulink can use char value?

Rik 2017-10-19

The only differences between my function and yours, is that mine is more compact, should be a tiny bit faster, doesn't overwrite n in the second loop, and returns a char vector instead of a double vector.

If you can use your function, you can also use mine. I hardly ever use Simulink at all, so I don't understand your question and can't answer it.

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