zeros before a string using num2str
显示 更早的评论
I would like to pad zeros before a string. I have the following code:
a1 = 12.1521;
a2 = 2.1521;
b1 = num2str(a1,'%03.4f');
b2 = num2str(a2,'%03.4f');
The result is b1 = '12.1521';
The result is b2 = '2.1521';
I would like to obtain the result b1 = '012.1521' and b2 = '002.1521'
采纳的回答
The problem with your format string is not the %0 which would work fine, had the next number been correct. The 3 is the problem. In both %3.4f and %03.4f it is ignored as the value is too small. It should always be more than the value after the . since it specifies the minimum total number of characters to print.
Try
num2str(a1, '%08.4f') %8 since you want 4 digits after the . + 1 digit for the . + 3 digit s before
更多回答（2 个）
Try this
A = [69.45 31.71 95.36 3.44 7.82]'
str = string(A)
newStr = pad(str,7,'left','0') %or pad(str,7,'both','0')
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