Error using sym/subsindex (line 796)

t1 = 588; %k
do = 3.5; % in
di = 3.0; % in
kp = 21.6; %W/(m*K)
ta = 294; % K
ts = 255.4; %k
h = 48.3; %W/(m^2*K)
deltar = 1; % in of calcium silicate insulation
e = .76;
at = pi*(do+2*deltar);
alm1 = (pi*(do-di))/(log(do/di));
alm2 = (2*pi*deltar)/log(do+2*deltar/do);
o = .0000000567; %W/(M^2*k^4)
d = .5; %do-di(in)
syms t2 t3 ki
eq1 = ki==.044+.0001144*(.5*(t2+t3)-283.333)
eq2 = 1/((d/(2*kp*alm1))+(deltar/ki*alm2))==(h*at(t3-ta)+e*o*at(t3^4-ts^4))/(t1-t3)
eq3 = (2*kp*alm1*(t1-t2))/((d)==h*at(t3-ta)+e*o*at(t3^4-ts^4))
[t2,t3,ki] = vpasolve([eq1,eq2,eq3],[t2,t3,ki],[0 inf;0 1])
t2 = double(t2)
t3 = double(t3)
ki = double(ki)
the error is in the eq2 line, eq1 seems to work fine.

4 个评论

In your code, ‘at’ is a single scalar value. It is not a function or an array, yet you are addressing it as one or the other (probably as a function) in ‘eq2’ and ‘eq3’.
You need to decide what you want to do with it.
Ended up fixing this problem! Was going to delete but figured if I could help someone else in the future then I'll leave it up. The problems in eq2 and eq3 were I needed *s in front of all the parentheses which I somehow forgot. Hope this helps someone!
@star strider I figured it out right before you answered! Thank you so much for the quick help!
The mystery nevertheless continues, since ‘s’ — either as a function or an array — appears nowhere in your code (that I can see).
Resolved it seems, regardless.

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 采纳的回答

Birdman
Birdman 2017-10-19
You forgot to put an operator in front of your at variables in eq2 and eq3. Also, in the vpasolve function, choose your initial guess wisely. If you don't indicate an initial guess for your equations, MATLAB still finds answers. Hope this helps.

1 个评论

I figured it out right before you answered! Thank you so much for the quick help!

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更多回答(1 个)

Walter Roberson
Walter Roberson 2017-10-19
You have at(t3-ta) and at(t3^4-ts^4) in that line, but at is not a function and and t3-ta and t3^4-ts^4 are not valid indices into the at variable

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