How to shift elements in a row matrix?
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Suppose i have a vector x=[1 1 1 1 0 0 1 1] i want 1 bit shifting such that the output is x1=[0 1 1 1 1 0 0 1] x2=[0 0 1 1 1 1 0 0]
How to do this??
采纳的回答
KL
2017-10-20
0 个投票
If you have access to Fixed-Point Designer toolbox, you could use bitsll
9 个评论
Darsana P M
2017-10-20
Wait! I got you all wrong. Yours simply a vector with 1s and 0s. I misread them as binary. "bit shifting" is not the right word.
Anyway, try the following code,
x=[1 1 1 1 0 0 1 1];
movex = @(z,a) [zeros(1,a) z(1:end-a)];
x1 = movex(x,1)
x2 = movex(x,2)
Darsana P M
2017-10-20
KL
2017-10-21
[zeros(1,a) z(1:end-a)]
if you read this, it adds 'a' number of zeros in the beginning and then neglects 'a' number of elements from z from behind. Do you understand? To do it the opposite way, you just need to modify it a tiny bit. Why don't you try and show me with how you tried?
Darsana P M
2017-10-21
KL
2017-10-22
Almost, but this time, you'd want to neglect the element from the beǵinning, so it should be,
[z(a+1:end) zeros(1,a)]
Darsana P M
2017-10-22
KL
2017-10-22
All of it should be of the same size, yes! If you used the code I showed you above, you'd get the result of exactly the same size.
Darsana P M
2017-10-22
更多回答（1 个）
Matt J
2017-10-20
x1=zeros(size(x));
x1(2:end)=x(1:end-1)
4 个评论
Darsana P M
2017-10-20
Matt J
2017-10-20
Why not?
Darsana P M
2017-10-21
Anu
2018-8-25
i want this code to execute for every iterations.I need to run it for 64 times and i need to display from 1to 64.how could i do this?
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