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How can I numerically find a solution of a series of two differential equations.

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So, I have to numerically find the solution to the following system (image attached) in a neighborhood of the equilibrium. Equilibrium in this case is x'(t)=0 & y'(t)=0.
Also these are the values of the constants. Alpha=4 Beta=3 L=2 k=1
What should be the MATLAB code for this? One friend suggested using ode45 but I do not know exactly how.
[In case you cannot view the image:
X’(t) = -alpha x(t) + k y(t)
Y’(t) = L x(t) – beta y(t)]

回答(1 个)

Roger Stafford
Roger Stafford 2017-10-26
编辑:Roger Stafford 2017-10-26
This is hardly a matlab problem. At an equilibrium you would have the equations:
-4*x + 1*y = 0
2*x - 3*y = 0
The only possible simultaneous solution for that is x = y = 0.
The general solution to that problem is:
x = C1*exp(-2*t)-C2*exp(-5*t)
y = 2*C1*exp(-2*t)+C2*exp(-5*t)
where C1 and C2 are constants depending on initial conditions of x and y. To arrive at a "neighborhood" of x' = 0 and y' = 0, you would have to approach infinity for t. In other words, equilibrium is only approached asymptotically.

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