For loop index problem

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Lydia Brown
Lydia Brown 2017-10-27
编辑： KL 2017-11-2
I have 3 variables called all_data_sess1, all_data_sess2 and all_data_sess3 which each contain a 216x8 matrix. When I run the following part of code below, the values for these variables change to just 216 and the matrix is gone, which I don't want. There are 216 rows and I want my for loop to go through each row, which is why I used to loop index 1:length(RT) (I also tried 1:216 but I get the same problem). I ran the whole script line by line and found when it gets to the bit of code below, the value for all_data_sess1 (or 2 or 3) get set to 1, and each time it goes through the for loop, 1 is added every time, hence the end result is all_data_sess1 = 216. How do I make it look at each row and not change/overwrite the matrix assigned to the variable?
for all_data_sess1 = 1:length(RT) %debugger shows running this line adds 1 to all_data_sess1 each time through the loop, rather than using it as a loop index.
if RT <= 2 %Disregarding RTs longer than 2 seconds Should this cutoff be sooner? RT <= 1.5?
if performance == 1 %Disregarding incorrect trials Is this the right way to organise 2 conditions?? if RT <= 2 && if performance == 1?
sortresultfunction %variables don't change, this isn't working...?
end
end
end
Thanks for any help!

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回答（1 个）

KL
KL 2017-11-2
编辑：KL 2017-11-2
you have to use another variable name as iterator in your for loop
for k = 1:size(all_data_sess1,1)
%here use k to index all_data_sess1, for example,
something = all_data_sess1(k,1);
...
...
end

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