how can i solve problem in my code for adaptive median filter

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function f= dd(r,Smax)
if (Smax <= 1) | (Smax/2 == round(Smax/2)) | (Smax ~= round(Smax))
error('SMAX must be an odd integer > 1.')
end
[M, N] = size(r);
% Initial setup.
f = r;
f(:) = 0;
alreadyProcessed = false(size(r));
%Begin filtering.
for k = 3:2:Smax
zmin = ordfilt2(r, 1, ones(k, k), 'symmetric');
zmax = ordfilt2(r, k * k, ones(k, k), 'symmetric');
zmed = medfilt2(r, [k k], 'symmetric');
processUsingLevelB = (zmed > zmin) & (zmax > zmed) & ...
~alreadyProcessed;
zB = (r > zmin) & (zmax > r);
outputZxy = processUsingLevelB & zB;
outputZmed = processUsingLevelB & ~zB;
f(outputZxy) = r(outputZxy);
f(outputZmed) = zmed(outputZmed);
alreadyProcessed = alreadyProcessed | processUsingLevelB;
if all(alreadyProcessed(:))
break;
end
end
% Output zmed for any remaining unprocessed pixels. Note that this
% zmed was computed using a window of size Smax-by-Smax, which is
% the final value of k in the loop.
f(~alreadyProcessed) = zmed(~alreadyProcessed);
  1 个评论
Daleel Ahmed
Daleel Ahmed 2017-10-28
编辑:Walter Roberson 2017-10-28
Error using ordfilt2
Expected input number 1, A, to be one of these types:
double, single, uint8, uint16, uint32, uint64, int8, int16, int32, int64, logical
Instead its type was char.

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采纳的回答

Walter Roberson
Walter Roberson 2017-10-28
You appear to be attempting to pass in characters for the first input to your function, the one named "r" here. That input must be numeric for this code to work.

更多回答(1 个)

Zeeshan Salam
Zeeshan Salam 2019-3-24
can u send me working of this algorithm and flowchart

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