Using an if/else statement inside of a for loop

Hi! I am trying to write an if else statement inside of a for loop in order to determine how many people surveyed had a specific response. I posted my code below. Every time I run it instead of generating the numbers, it generates my fprintf statement that amount of time. I am just really confused because I followed the template my professor gave and it just isn't working for me. Thank you,
y=load('Class19_survey.txt');
ag=0;
ne=0;
dis=0;
for k=1:length(y)
if y(k)>=4
ag=ag+1;
fprintf('\nThe number of people who agree is\n',ag)
elseif y(k)==3
ne=ne+1
fprintf('\nThe number of neutral responses is\n',ne)
else y(k)<=2
dis=dis+1
fprintf('\nThe number of disagree responses is\n', dis)
end
end

1 个评论

Sorry here is an easier version to read
y=load('Class19_survey.txt');
ag=0;
ne=0;
dis=0;
for k=1:length(y)
if y(k)>=4
ag=ag+1;
fprintf('\nThe number of people who agree is\n',ag)
elseif y(k)==3
ne=ne+1
fprintf('\nThe number of neutral responses is\n',ne)
else y(k)<=2
dis=dis+1
fprintf('\nThe number of disagree responses is\n', dis)
end
end

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 采纳的回答

Perhaps you want something like this,
y=load('Class19_survey.txt');
ag=0;
ne=0;
dis=0;
for k=1:length(y)
if y(k)>=4
ag=ag+1;
elseif y(k)==3
ne=ne+1;
else y(k)<=2
dis=dis+1;
end
end
fprintf('\nThe number of people who agree is\n',ag)
fprintf('\nThe number of neutral responses is\n',ne)
fprintf('\nThe number of disagree responses is\n', dis)
but you could also do it without the loop and if statements,
ag = length(y(y>=4));
ne = length(y(y==3));
dis = length(y(y<=2));

更多回答(1 个)

y=load('Class19_survey.txt');
ag=0;
ne=0;
dis=0;
for k=1:length(y)
if y(k)>=4
ag=ag+1;
elseif y(k)==3
ne=ne+1;
else y(k)<=2
dis=dis+1;
end
end
fprintf('\nThe number of people who agree is\n',ag);
fprintf('\nThe number of neutral responses is\n',ne);
fprintf('\nThe number of disagree responses is\n', dis);

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