Simple Linear Algebra problem that's confusing me.
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I'm stuck for the longest time on this problem: Find a row vector l such that lA = l, with A = [.2 .8; .7 .3]. This is somehow related to eigenvalues, is there such thing as a row eigenvector? thanks - Yingquan
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Richard Brown
2012-4-26
a "row" eigenvector is usually called a left eigenvector
回答（1 个）
Wayne King
2012-4-25
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I don't want to just give you the answer, but think of it this way
1.) Think of the typical eigenvalue problem, I'll use B as the matrix
Bx = \lambda x
2.) if 1 were an eigenvalue of B with some corresponding eigenvector x, then
Bx = x
3.) Now what if you transposed both sides of the above equation and let B'=A (where ' is the transpose)
Now do you see?
2 个评论
Antony Chung
2012-4-26
Are you saying to do B'*x'=x'?
3.) confused me a little bit.
Richard Brown
2012-4-26
don't forget the rule about transposing products ...
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2012-4-25
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